Question

2) 7x - 14>0. 2x >8; (4) (2x +7>0, 5x + 15 >0.​

Answer 1

Ответ: см фото.

Объяснение:

Answer 2

Let's solve each inequality separately:

1. $7x - 14 > 0$

   First, add 14 to both sides:

   $7x > 14$

   Now, divide both sides by 7:

   $x > 2$

   So, the solution to this inequality is $x > 2$.

2. $2x > 8$

   Divide both sides by 2:

   $x > 4$

   The solution to this inequality is $x > 4$.

3. $2x + 7 > 0$

   Subtract 7 from both sides:

   $2x > -7$

   Divide both sides by 2:

   $x > -\frac{7}{2}$

   So, the solution to this inequality is $x > -\frac{7}{2}$.

4. $5x + 15 > 0$

   Subtract 15 from both sides:

   $5x > -15$

   Divide both sides by 5:

   $x > -3$

   So, the solution to this inequality is $x > -3$.

Now, let's find the intersection of the solutions:

The common solution to all four inequalities is $x > 4$, as it satisfies all the given conditions. Therefore, the combined solution to the system of inequalities is $x > 4$.