Question

(3x^2+5xy+7x^2y)-(5xy+3x^2)-(7x^2y-3x^2) срочно помогите ПЛИЗ!

Answer 1

Ответ:

$(3x^2+5xy+7x^2y)-(5xy+3x^2)-(7x^2y-3x^2)=3x ^2+5xy+7x ^2y-5xy-3x ^2-(7x ^2y-3x ^2 )=3x ^2+7x ^2 y-3x ^2-(7x ^2 y-3x ^2 )=7x ^2 y-7x ^2 y+3x ^2=3x ^2$

Объяснение:

Answer 2

To simplify the expression (3x^2 + 5xy + 7x^2y) - (5xy + 3x^2) - (7x^2y - 3x^2), we can combine like terms and perform the necessary operations. Let's break it down step by step:

Step 1: Distribute the negative sign

We need to distribute the negative sign to each term inside the parentheses. This means that the expression becomes:

(3x^2 + 5xy + 7x^2y) - 5xy - 3x^2 - 7x^2y + 3x^2

Step 2: Combine like terms

Now, let's combine the like terms. We have the following terms:

- 3x^2 + 7x^2y - 3x^2 (the x^2 terms) - 5xy - 5xy (the xy terms)

The terms with x^2 cancel each other out, and the terms with xy also cancel each other out. Therefore, the simplified expression is:

0

So, the simplified form of (3x^2 + 5xy + 7x^2y) - (5xy + 3x^2) - (7x^2y - 3x^2) is 0.

I hope this helps! Let me know if you have any further questions.