Question

В авіакасі було 15 квитків, серед яких 6 — до Львова. До кінця зміни було реалізовано 8 квитків. Знайдіть імовірність того, що в касі не залишилось квитків до Львова, якщо ймовірність продажу кожного квитка однакова.

Answer 1

Ответ:

4/715=0.0055944

Объяснение:

p=C(6,6)*C(15-6,8-6)/C(15,8)=4/715=0.0055944

Answer 2

To find the probability that there are no tickets left to Lviv, given that the probability of selling each ticket is the same, we can use the concept of independent events.

Let's break down the information given: - There were a total of 15 tickets. - Out of these 15 tickets, 6 were for Lviv. - By the end of the shift, 8 tickets were sold.

To find the probability that no tickets to Lviv are left, we need to calculate the probability of selling all 6 tickets to Lviv. Since the probability of selling each ticket is the same, we can assume that the probability of selling a ticket to Lviv is 6/15.

To calculate the probability of selling all 6 tickets to Lviv, we multiply the probabilities of selling each ticket together. Since the events are independent, we can multiply the probabilities:

P(selling all 6 tickets to Lviv) = (6/15) * (6/15) * (6/15) * (6/15) * (6/15) * (6/15)

Simplifying this expression, we get:

P(selling all 6 tickets to Lviv) = (6/15)^6

Calculating this probability, we find:

P(selling all 6 tickets to Lviv) ≈ 0.0138

Therefore, the probability that no tickets to Lviv are left is approximately 0.0138, or 1.38%.

Please note that this calculation assumes that the probability of selling each ticket is the same and that the events are independent.