Question

Решить уравнение 9x^2+3x-2=0

Answer 1

Ответ:

D= 9+4*9*(-2)=81=9

x1= -3+9/18=6/18=1/3

x2=-3-9/18=-2/3

Объяснение:

Answer 2

Вот так. Но я не очень уверена:(

Answer 3

I can help you solve the equation $9x^2+3x-2=0$ in detail. First, we need to find the discriminant of the equation, which is $D=b^2-4ac$, where $a=9$, $b=3$, and $c=-2$. Plugging in these values, we get $D=3^2-4(9)(-2)=81$. Since $D>0$, the equation has two real roots, which are given by the formula $x=\frac{-b\pm\sqrt{D}}{2a}$. Substituting the values of $a$, $b$, and $D$, we get $x=\frac{-3\pm\sqrt{81}}{18}$. Simplifying, we get $x=\frac{-3\pm9}{18}$. This gives us two possible values for $x$: $x=\frac{-3+9}{18}=\frac{1}{3}$ or $x=\frac{-3-9}{18}=-\frac{2}{3}$. Therefore, the solution set of the equation is $\{ \frac{1}{3}, -\frac{2}{3} \}$. You can check your answer by plugging in these values into the original equation and verifying that they make it true. For more information on how to solve quadratic equations, you can visit [this website](https://ru.symbolab.com/solver/equation-calculator) or [this one](https://mathsolver.microsoft.com/ru/algebra-calculator). I hope this helps. Have a nice day.