Question

1) 8a² – 8aв – 5а + 5в, если а = 1/8 , в = -3/4; 2) 10х³ + х² + 10х + 1, если х = 0,3.Помогите пожалуйста

Answer 1

Ответ:

8а²-8ав-5а+5в=8а(а-в)-5(а-в)=(8а-5)(а-в)

а=1/8   в=-3/4

(8*1/8-5)(1/8-(-3/4)=-4*7/8=-7/2=-3 1/2

10х³+х²+10х+1=10х(х²+1)+(х²+1)=(10х+1)(х²+1)

х=0.3

(10*0.3+1)((0.3)²+1)=4*1.09=4.36

Объяснение:

Answer 2

1) To find the value of the expression 8a² - 8ab - 5a + 5b when a = 1/8 and b = -3/4, we can substitute these values into the expression and simplify.

Substituting a = 1/8 and b = -3/4 into the expression, we get:

8(1/8)² - 8(1/8)(-3/4) - 5(1/8) + 5(-3/4)

Simplifying each term, we have:

8(1/64) + 8(3/32) - 5/8 - 15/4

Multiplying and adding fractions, we get:

1/8 + 3/4 - 5/8 - 15/4

Combining like terms, we have:

(1/8 - 5/8) + (3/4 - 15/4)

-4/8 + (-12/4)

-1/2 - 3

-7/2

Therefore, when a = 1/8 and b = -3/4, the value of the expression 8a² - 8ab - 5a + 5b is -7/2.

2) To find the value of the expression 10x³ + x² + 10x + 1 when x = 0.3, we can substitute this value into the expression and simplify.

Substituting x = 0.3 into the expression, we get:

10(0.3)³ + (0.3)² + 10(0.3) + 1

Simplifying each term, we have:

10(0.027) + 0.09 + 3 + 1

0.27 + 0.09 + 3 + 1

Combining like terms, we have:

0.36 + 4

4.36

Therefore, when x = 0.3, the value of the expression 10x³ + x² + 10x + 1 is 4.36.