Question

помогите пожалуста укажите выражение торжественно равное выражению1 (p-q)^2 A p^2 -q^2 B p^2+2pq+q^2 2(x-c)(x+c) A x^2 -2cx+c^2 B x^2 -c^2 3

Answer 1

Ответ:

1. (p-q)² = p²-2pq+q²

2. (x-c)(x+c) = x²-c²

Answer 2

I can help you with your math problem.

The expression you wrote is equivalent to $$2A + 2B + 4pq + 4x^2 - 4cx + 6$$

To simplify it, you can use the following steps:

- Expand the brackets using the formula $(a-b)^2 = a^2 - 2ab + b^2$ and $(a+b)(a-b) = a^2 - b^2$. - Collect the like terms and add or subtract them. - Factor out any common factors if possible.

I hope this helps you. If you need more explanation, you can ask me to show you the steps in detail.Ответь+подробно.++помогите+пожалуста+укажите+выражение+торжественно+равное+выражению1+(p-q)^2+A+p^2+-q^2+B+p^2+2pq+q^2+2(x-c)(x+c)+A+x^2+-2cx+c^2+B+x^2+-c^2+3+