Question

Из города в деревню, расстояние между которыми 75 км, одновременно выехали автомобились и велосипедист. Скорость автомобилиста на 40 км/ч больше скорости велосипедиста. Найди скорость велосипедиста, если известно, что он прибыл в деревню на бч позже автомобилиста.​

Answer 1

Ответ:

вот тебе решение...........................

Объяснение:

Answer 2

Problem Analysis

We are given that the distance between a city and a village is 75 km. An automobile and a cyclist simultaneously start their journey from the city to the village. The speed of the automobile is 40 km/h faster than the speed of the cyclist. We need to find the speed of the cyclist if we know that the cyclist arrived at the village one hour later than the automobile.

Solution

Let's assume the speed of the cyclist is x km/h. Since the speed of the automobile is 40 km/h faster, the speed of the automobile is x + 40 km/h.

We know that the time taken by both the cyclist and the automobile to cover the distance of 75 km is the same, except that the cyclist arrived one hour later than the automobile. Therefore, we can set up the following equation:

75 / x = 75 / (x + 40) + 1

To solve this equation, we can cross-multiply and simplify:

75(x + 40) = 75x + x(x + 40)

Simplifying further:

75x + 3000 = 75x + x^2 + 40x

Combining like terms:

x^2 + 40x - 3000 = 0

Now we have a quadratic equation. We can solve it by factoring or using the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 1, b = 40, and c = -3000. Substituting these values into the formula:

x = (-40 ± √(40^2 - 4(1)(-3000))) / (2(1))

Simplifying further:

x = (-40 ± √(1600 + 12000)) / 2

x = (-40 ± √(13600)) / 2

x = (-40 ± 116.6) / 2

Now we have two possible values for x:

x1 = (-40 + 116.6) / 2 = 38.3 x2 = (-40 - 116.6) / 2 = -78.3

Since speed cannot be negative, we discard the negative value. Therefore, the speed of the cyclist is 38.3 km/h.

Answer

The speed of the cyclist is 38.3 km/h.