Question

Решите неравенство(подробно)-x²-2,6x-1,6<0​

Answer 1

Ответ:

см ниже

Объяснение:

для начала умножим на -1. сменим все знаки .

x²+2,6x+1,6 больше 0​

далее решаем квадратное уравнение через Д

х1,2= 2.6 +- корень из 2.6*2.6-4*1.6 все это делить на 2

получается (2.6+-0.6)/2

х1=2.6+0.6  делить на 2 = 1.6

х2=2.6-0.6 делить на 2 = 1

отмечаем эти точки на оси

левее будет точка 1.  проверяем интервалы. берем 0 из крайнего левого. получаем -1.6 меньше 0. подходит.

далее знаки чередуются . ответ (-∞;1) ∪(1.6:∞)

Answer 2

I can help you with solving inequalities. Here is the detailed solution for your problem:

To solve the inequality $-x^2-2.6x-1.6<0$, we need to find the values of $x$ that make the expression negative. We can do this by factoring the expression and finding its roots.

The expression $-x^2-2.6x-1.6$ can be factored as $-(x+2)(x+0.8)$. The roots are $x=-2$ and $x=-0.8$. These are the points where the expression is equal to zero.

To find the intervals where the expression is negative, we can use a sign chart. We divide the number line into three regions based on the roots: $(-\infty, -2)$, $(-2, -0.8)$, and $(-0.8, \infty)$. Then we pick a test value in each region and plug it into the expression to see its sign.

For example, in the region $(-\infty, -2)$, we can pick $x=-3$ as a test value. Plugging it into the expression, we get $-(-3)^2-2.6(-3)-1.6=-9+7.8-1.6=-2.8$. This is negative, so we mark this region with a minus sign.

Similarly, in the region $(-2, -0.8)$, we can pick $x=-1$ as a test value. Plugging it into the expression, we get $-(-1)^2-2.6(-1)-1.6=-1+2.6-1.6=0$. This is zero, so we mark this region with a zero sign.

In the region $(-0.8, \infty)$, we can pick $x=0$ as a test value. Plugging it into the expression, we get $-(0)^2-2.6(0)-1.6=-1.6$. This is negative, so we mark this region with a minus sign.

The sign chart looks like this:

|-----|-----|-----| | - | 0 | - | |-----|-----|-----| |<--(-2)--|<--(-0.8)--|<--(+∞)--|

The expression is negative in the regions marked with a minus sign. Therefore, the solution set for the inequality is $(-\infty, -2) \cup (-0.8, \infty)$. This means that any value of $x$ that is less than $-2$ or greater than $-0.8$ will satisfy the inequality.

I hope this helps you understand how to solve inequalities. If you have any other questions, feel free to ask me.Ответь+подробно.++Решите+неравенство(подробно)-x²-2,6x-1,6<0​+