Question

Склади квадратне рівняння коренями якого є числа х1= -9; х2= -12, А коефіцієнт а= 1. Срочно!!!

Answer 1

Ответ: х²+21х+108=0

Объяснение:

(х+9)*(х+12)=0

х²+12х+9х+108=0

х²+21х+108=0

Answer 2

Quadratic Equation with Given Roots

To find the quadratic equation with the given roots, we can use the fact that if \( x_1 \) and \( x_2 \) are the roots of the quadratic equation \( ax^2 + bx + c = 0 \), then the equation can be expressed as \( a(x - x_1)(x - x_2) = 0 \).

Given roots: \( x_1 = -9 \) and \( x_2 = -12 \)

Using the formula, we can find the quadratic equation.

Finding the Quadratic Equation

The quadratic equation with the given roots can be expressed as:

\[ a(x - x_1)(x - x_2) = 0 \]

Substitute the given values of \( x_1 \) and \( x_2 \):

\[ a(x + 9)(x + 12) = 0 \]

Now, we can expand this expression to find the quadratic equation.

\[ a(x^2 + 12x + 9x + 108) = 0 \] \[ a(x^2 + 21x + 108) = 0 \]

So, the quadratic equation with the given roots \( x_1 = -9 \) and \( x_2 = -12 \) and coefficient \( a = 1 \) is:

\[ x^2 + 21x + 108 = 0 \]

This is the quadratic equation with the specified roots and coefficient.

I hope this helps! If you have any other questions, feel free to ask.