Question

Помогите решить пж даю 25 балов!!!! 1) (x+4)² 2) (y-5)² 3) (6-x)² 4) (7+z)² 5) (2x-5y)² 6) (18x-11y)² 7) (3a+1)² 8) (5c-3g)² 9) (11p+4k)² 10) (1/3x+1/2y)² 11) (x-4) (x+4) 12) (11-a) (11+a) 13) (6a-2b) (2b+6a) 14) x²-100 15) 16b²-25c² 16) 1/81a²-1/64b²

Answer 1

x²+8x+16

y²-10y+25

36-12x+x²

49+14z+z²

4x²-20xy+25y²

324x²-382xy+121y²

9a²+6a+1

25c²-30cg+9g²

121p²+88pk+16k²

¹/9x²+2/6xy+¼y²

x²-16

121-a²

36a²-4b²

(x-10)(x+10)

(4b-5c)(4b+5c)

(1/9a-1/8b)(1/9a+1/8b)

Answer 2

1. (x+4)² = x² + 8x + 16
2. (y-5)² = y² - 10y + 25
3. (6-x)² = x² - 12x + 36
4. (7+z)² = z² + 14z + 49
5. (2x-5y)² = 4x² - 20xy + 25y²
6. (18x-11y)² = 324x² - 396xy + 121y²
7. (3a+1)² = 9a² + 6a + 1
8. (5c-3g)² = 25c² - 30cg + 9g²
9. (11p+4k)² = 121p² + 88pk + 16k²
10. (1/3x+1/2y)² = 1/9x² + 1/6xy + 1/4y²
11. (x-4)(x+4) = x² - 16
12. (11-a)(11+a) = 121 - a²
13. (6a-2b)(2b+6a) = 36a² - 4ab + 12ab + 36b² = 36a² + 8ab + 36b²
14. x²-100 = (x-10)(x+10)
15. 16b²-25c² = (4b+5c)(4b-5c)
16. 1/81a²-1/64b² = (1/9a + 1/8b)(1/9a - 1/8b)