Question

(3a-2)²- (3a+1)(a+5)

Answer 1

Ответ:

(3a-2)²-(3a+1)(a+5)

9a²-12a+4-(3a²+15a+a+5)

9a²-12a+4-(3a²+16a+5)

9a²-12a+4-3a²-16a-5

6a²-28a-1

Answer 2

${(3a - 2)}^{2} - (3a + 1)(a + 5) = {9a}^{2} - 12a + 4 - ( {3a}^{2} + 15a + a + 5) = {9a}^{2} - 12a + 4 - {3a}^{2} - 15a - a - 5 = {6a}^{2} - 28a - 1$

Answer 3

To simplify the expression (3a-2)² - (3a+1)(a+5), let's start by expanding the square:

(3a-2)² = (3a-2)(3a-2) = 9a² - 6a - 6a + 4 = 9a² - 12a + 4

Next, we can expand the second term:

(3a+1)(a+5) = 3a(a+5) + 1(a+5) = 3a² + 15a + a + 5 = 3a² + 16a + 5

Now, substituting these expanded forms into the original expression, we have:

(3a-2)² - (3a+1)(a+5) = (9a² - 12a + 4) - (3a² + 16a + 5)

Expanding further by distributing the negative sign to the terms inside the parentheses, we get:

= 9a² - 12a + 4 - 3a² - 16a - 5

Combining like terms, we have:

= (9a² - 3a²) + (-12a - 16a) + (4 - 5) = 6a² - 28a - 1

So, the simplified form of (3a-2)² - (3a+1)(a+5) is 6a² - 28a - 1.