Question

9+16x+64+8+16xy=0

Answer 1

Ответ:

d y. 9x+8+8y

---- = -- ----------

d x 8(y+x)

Объяснение:

вот правелный вапрос

Answer 2

The equation you've provided is a quadratic equation in two variables, x and y. To solve it, we can rearrange the terms and try to factorize or apply the quadratic formula. However, since you didn't specify any specific instructions or constraints, I'll assume that you want to solve it generally for x and y.

The equation you provided is: 9 + 16x + 64 + 8 + 16xy = 0

Combining like terms, we have: 81 + 16x + 16xy = 0

Now, let's try to solve for x and y.

To isolate x, we can treat y as a constant and rewrite the equation as a quadratic equation in terms of x: 16xy + 16x + 81 = 0

Using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), where a = 16y, b = 16, and c = 81, we can substitute these values:

x = (-16 ± √(16^2 - 4(16y)(81))) / (2(16y))

Simplifying further, we have: x = (-16 ± √(256 - 64y(81))) / (32y)

Similarly, to isolate y, we can treat x as a constant and rewrite the equation as a quadratic equation in terms of y: 16xy + 16x + 81 = 0

Using the quadratic formula: y = (-b ± √(b^2 - 4ac)) / (2a), where a = 16x, b = 16, and c = 81, we can substitute these values:

y = (-16 ± √(16^2 - 4(16x)(81))) / (2(16x))

Simplifying further, we have: y = (-16 ± √(256 - 64x(81))) / (32x)

So, the solutions for x and y are given by these expressions.