Question

6(x+2)-(25x²+27)=(3-5хв)(3+5хв)

Answer 1

Ответ:

х=4 у меня так вышло думаю помог

Answer 2

Let's solve the equation step by step:

1. Simplify the left side of the equation: 6(x + 2) - (25x² + 27)

Expand the multiplication: 6x + 12 - 25x² - 27

Combine like terms: -25x² + 6x - 15

2. Simplify the right side of the equation: (3 - 5хв)(3 + 5хв)

This expression is in the form of a difference of squares: (a - b)(a + b) = a² - b²

Using this formula, we can rewrite the right side of the equation: (3)² - (5хв)²

Expand the squares: 9 - 25хв²

3. Now we have the equation: -25x² + 6x - 15 = 9 - 25хв²

4. Rearrange the equation to bring all terms to one side: -25x² + 6x - 15 - 9 + 25хв² = 0

Combine like terms: -25x² + 6x - 24 + 25хв² = 0

5. The equation is now in the form of a quadratic equation. We can solve it by factoring, completing the square, or using the quadratic formula. However, it seems there is a typographical error in the equation you provided. The terms "хв" appear instead of "x²" in the right side of the equation.

If you can clarify the correct equation or provide more information, I would be happy to help you solve it.