Question

2)а(3х-2у+5)-2а(-2х-у)= ​

Answer 1

Ответ: =7xa+5a

Объяснение: а(3х-2у+5)-2а(-2х-у)= ​3ax-2ay+5a+4ax+2ay=

=7xa+5a

Answer 2

Ответ:$7ax+5a$

Объяснение: $a*(3x-2y+5)-2a(-2x-y)=$

(множим а на дужку)

$3ax-2ay+5a-2a*(-2x-y)=$

(множим -2а на дужку)

$3ax-2ay+5a+4ax+2ay=$

(сокращаем -2ау и 2ау)

$3ax+5a+4ax=$

( добавляем 3ах и 4ах)

$7ax+5a$

Answer 3

To simplify the expression, let's distribute the coefficients:

2(a(3x - 2y + 5)) - 2a(-2x - y)

First, let's simplify the expression inside the parentheses:

2(3ax - 2ay + 5a) - 2a(-2x - y)

Now distribute the coefficients:

6ax - 4ay + 10a - 4ax - 2ay

Combine like terms:

(6ax - 4ax) + (-4ay - 2ay) + 10a

2ax - 6ay + 10a

Therefore, 2(a(3x - 2y + 5)) - 2a(-2x - y) simplifies to 2ax - 6ay + 10a.