Question

Sin²A-cos²A-sin A-cos A​

Answer 1

Ответ:

Разложим на множители , применив формулу разности квадратов .

$\bf sin^2A-cos^2A-sinA-cosA=\\\\=(sinA-cosA)(sinA+cosA)-(sinA+cosA)=\\\\=(sinA+cosA)(sinA-cosA-1)$

Answer 2

To simplify the expression sin²A - cos²A - sin A - cos A, we can use trigonometric identities.

First, let's rewrite cos²A as 1 - sin²A using the Pythagorean identity for cosine:

sin²A - (1 - sin²A) - sin A - cos A

Next, distribute the negative sign:

sin²A - 1 + sin²A - sin A - cos A

Combine like terms:

2sin²A - sin A - cos A - 1

So, the simplified expression is 2sin²A - sin A - cos A - 1.