Question

(х -5 ) (х + 5) ~(2х+1) (х -2 ) = 1 - х2.

Answer 1

Удачи. Надеюсь правельно

Answer 2

To solve the equation, let's simplify both sides and then proceed with solving for x.

Expanding the left side of the equation: (x - 5)(x + 5) = (2x + 1)(x - 2) x^2 - 5x + 5x - 25 = 2x^2 - 4x + x - 2 x^2 - 25 = 2x^2 - 3x - 2

Moving all terms to one side of the equation: 0 = 2x^2 - x - 2x^2 + 3x + 2 - 25 0 = 2x^2 - x - 2x^2 + 3x - 23 0 = 2x^2 - 2x^2 - x + 3x - 23 0 = 0x^2 + 2x - 23

Simplifying further: 0x^2 + 2x - 23 = 0

Now we have a quadratic equation. We can solve it by factoring, completing the square, or using the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our equation, a = 0, b = 2, and c = -23. Substituting the values into the formula:

x = (-2 ± √(2^2 - 4(0)(-23))) / (2(0)) x = (-2 ± √(4 + 0)) / 0 x = (-2 ± √4) / 0 x = (-2 ± 2) / 0

Since we have division by zero, this equation doesn't have a solution in the real number system.