Question

Подайте у выгляді добутку многочлен: 1) 12b²- 12c²; 2)2a²c- 2b²c; 3)5a²- 20; 4)3mn²- 48m; 5)7y³-7y; 6)a³- a⁵

Answer 1

Ответ:

1) ... =12(b+c)(b-c)

2) ... =2c(a+b)(a-b)

3) ... = 5(a+2)(a-2)

4) ... = 3m(n+2)(n-2)

5) ... = 7y(y+1)(y-1)

6) ... = a$^{3}$(1-a)(1+a)

Объяснение:

Answer 2

Объяснение:

1) 12 × (b² - c²)

2) 2c × (a² - b²)

3) 5 × (a² - 4)

4) 3m × (n² - 16)

5) 7y × (y² - 1)

6) a³ × (1 - a²)

Answer 3

1. 12b² - 12c² can be factored as 12(b² - c²), which is the difference of squares. Thus, the expression can be written as 12(b + c)(b - c).

2. 2a²c - 2b²c can be factored as 2c(a² - b²), which is again the difference of squares. Therefore, the expression can be written as 2c(a + b)(a - b).

3. 5a² - 20 can be factored as 5(a² - 4), which is again the difference of squares. Hence, the expression can be written as 5(a + 2)(a - 2).

4. 3mn² - 48m can be factored as 3m(n² - 16), which is once again the difference of squares. Therefore, the expression can be written as 3m(n + 4)(n - 4).

5. 7y³ - 7y can be factored as 7y(y² - 1), which is the difference of squares. Hence, the expression can be written as 7y(y + 1)(y - 1).

6. a³ - a⁵ can be factored as a³(1 - a²). Therefore, the expression can be written as a³(1 + a)(1 - a²).