Question

11,2 m³ + 830 dm³ + 56 m³

Answer 1

Ответ:

A

m

3

=20m

m(m−1)(m−2)=20m

(m−1)(m−2)=20

m

2

−3m−18=0

D=81,m

1

=

2

3−9

=−3,m

2

=

2

3+9

=6,(m∈N)

text\Otvet:m=6.

Объяснение:

лютый пон

Answer 2

To perform the addition of the given volumes, we need to ensure that all the volumes are in the same unit. Let's convert the given volumes to cubic meters before adding them:

1. Convert 830 dm³ to cubic meters: Since 1 dm³ is equal to 0.001 m³, we can convert dm³ to m³ by multiplying by 0.001. Therefore, 830 dm³ = 830 * 0.001 m³ = 0.83 m³.

2. Now we have: 11.2 m³ + 0.83 m³ + 56 m³

Adding the volumes together: 11.2 m³ + 0.83 m³ + 56 m³ = 68.03 m³

Therefore, the sum of the given volumes is 68.03 m³.