Question

6) 8x - 9 - 3(4x - 12) 1-2x; B) 9(x+2)-7, 2(2x + 1) >= 1 ,8+0,9x,\\ 10x-6,5(x-2)​

Answer 1

Ответ:

на фото

Объяснение:

Надеюсь понятно

Answer 2

Let's simplify the given expressions one by one:

A) 8x - 9 - 3(4x - 12) - (1-2x) = 8x - 9 - 12x + 36 - 1 + 2x (distributing the negative sign) = (8x - 12x + 2x) - (9 + 36 - 1) = -2x - (9 + 36 - 1) = -2x - 44

B) 9(x+2) - 7 ≥ 2(2x + 1) Distributing on both sides: 9x + 18 - 7 ≥ 4x + 2 9x + 11 ≥ 4x + 2 Subtracting 4x from both sides: 5x + 11 ≥ 2 Subtracting 11 from both sides: 5x ≥ -9 Dividing by 5 (note: we must reverse the inequality because we are dividing by a negative number): x ≤ -9/5

C) 8 + 0.9x > 10x - 6 + 5(x - 2) Distributing on both sides: 8 + 0.9x > 10x - 6 + 5x - 10 Combining like terms: 8 + 0.9x > 15x - 16 Subtracting 15x from both sides: -14.1x + 8 > -16 Subtracting 8 from both sides: -14.1x > -24 Dividing by -14.1 (note: we must reverse the inequality because we are dividing by a negative number): x < 24/14.1

I hope this helps! Let me know if you have any further questions.