Question

(z-5)^2+3(z-8) при x=-0 2

Answer 1

Нужно знать: (a - b)² = a² - 2ab + b².

Поэтому:

(z - 5)² + 3(z - 8) = z² - 10z + 25 + 3z - 24 = z² - 7z + 1.

при z = -0 2    z² - 7z + 1 = (-0,2)² - 7 · (-0,2) + 1 = 0,04 + 1,4 + 1 = 2,44.

Ответ: 2, 44.

Answer 2

To evaluate the expression (z-5)^2 + 3(z-8) when z = -0 and z = 2, we substitute these values into the expression and perform the calculations.

For z = -0: ((-0) - 5)^2 + 3((-0) - 8) (-5)^2 + 3(-8) 25 + (-24) 1

For z = 2: ((2) - 5)^2 + 3((2) - 8) (-3)^2 + 3(-6) 9 + (-18) -9

Therefore, when z = -0, the expression evaluates to 1, and when z = 2, the expression evaluates to -9.