Question

(2x-1)*(4xво 2 степени +2x+1)

Answer 1

$(2x - 1) \times (4x {}^{2} + 2x + 1) \\ (2x) {}^{3} - 1 {}^{3} \\ 8x {}^{3} - 1$

Answer 2

To multiply these two expressions, we need to distribute the first term of the first expression, which is 2x, to each term of the second expression, and then distribute the second term of the first expression, which is -1, to each term of the second expression. This gives:

(2x - 1) * (4x^2 + 2x + 1) = 2x * (4x^2) + 2x * (2x) + 2x * (1) - 1 * (4x^2) - 1 * (2x) - 1 * (1) = 8x^3 + 4x^2 + 2x - 4x^2 - 2x - 1 = 8x^3 - 1

Therefore, (2x - 1) * (4x^2 + 2x + 1) simplifies to 8x^3 - 1.