Question

Решите уравнения: а) x²+х=0 б)х²-4х+3=0 в)5х²+14х-3=0 г)х²-2х-2=0 д)5х=3х² е)х²-5х+4=0 ж)7х²-4=0 з)3х²-х+2=0

Answer 1

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Answer 2

а) x² + x = 0 x(x + 1) = 0 x = 0 or x = -1

б) x² - 4x + 3 = 0 (x - 3)(x - 1) = 0 x = 3 or x = 1

в) 5x² + 14x - 3 = 0 Using the quadratic formula: x = (-14 ± √(14² - 4(5)(-3))) / (2(5)) x = (-14 ± √(256)) / 10 x = (-14 ± 16) / 10 x = (-3/5) or x = (1/5)

г) x² - 2x - 2 = 0 Using the quadratic formula: x = (2 ± √(2² - 4(1)(-2))) / (2(1)) x = (2 ± √(12)) / 2 x = 1 ± √3

д) 5x = 3x² 3x² - 5x = 0 x(3x - 5) = 0 x = 0 or x = 5/3

е) x² - 5x + 4 = 0 (x - 4)(x - 1) = 0 x = 4 or x = 1

ж) 7x² - 4 = 0 7x² = 4 x² = 4/7 x = ±√(4/7)

з) 3x² - x + 2 = 0 Using the quadratic formula: x = (1 ± √(1² - 4(3)(2))) / (2(3)) x = (1 ± √(-23)) / 6 x = (1/6) ± ((√23)i / 6), where i is the imaginary unit.