Question

X²+1,5=0 2x²-11+12=0

Answer 1

X^2 + 1,5 = 0
x^2 = - 1,5
x ∈ ∅, нет решений

2x^2 - 11 + 12 = 0
2x^2 + 1 = 0 
2x^2 = - 1
x^2 = - 0,5
x ∈ ∅, нет решений

Answer 2

To solve the first equation, X²+1,5=0, we can use the quadratic formula:

X = (-b ± sqrt(b² - 4ac)) / 2a

In this case, a = 1, b = 0, and c = 1.5. Substituting these values into the formula, we get:

X = (-0 ± sqrt(0² - 4(1)(1.5))) / 2(1) X = ± sqrt(-6) / 2

Since the square root of a negative number is not a real number, there are no real solutions to this equation.

To solve the second equation, 2x²-11x+12=0, we can factor it into two binomials:

2x²-11x+12 = (2x - 3)(x - 4) = 0

Setting each factor equal to zero, we get:

2x - 3 = 0 or x - 4 = 0

Solving for x in each equation, we get:

2x = 3 or x = 4

x = 3/2 or x = 4

Therefore, the solutions to the second equation are x = 3/2 or x = 4.