Question

(x-1)(x+1)-x(x-3)=0 (x-6)(x+6)-(2x-3)(x-1)=6-x2

Answer 1

Вот и решение . Там во втором уравнение чуть не хватает до решать надо

Answer 2

To solve the equation (x-1)(x+1)-x(x-3)=0, we can expand the left-hand side and simplify:

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(x-1)(x+1)-x(x-3) = x^2 - 1^2 - x^2 + 3x
                   = 2x - 1

So we have 2x - 1 = 0, which gives x = 1/2.

To solve the equation (x-6)(x+6)-(2x-3)(x-1)=6-x^2, we can expand and simplify the left-hand side:

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(x-6)(x+6)-(2x-3)(x-1) = x^2 - 6^2 - (2x^2 - 5x + 3)
                        = -x^2 - 5x - 45

Substituting this into the original equation, we get:

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-x^2 - 5x - 45 = 6 - x^2

Simplifying, we get x = -9.

Therefore, the solutions to the equations are x = 1/2 and x = -9.