Question

1) x(x+3)=3x 2) (3x-2)(3x+2)=5

Answer 1

1   х=0
2.    х=1
.................................................

Answer 2

1. To solve the equation x(x+3) = 3x, we can start by simplifying the left-hand side:

x(x+3) = x^2 + 3x

Now we can substitute this expression into the original equation:

x^2 + 3x = 3x

Simplifying further:

x^2 = 0

Taking the square root of both sides, we get:

x = 0

Therefore, the solution to the equation x(x+3) = 3x is x = 0.

2. To solve the equation (3x-2)(3x+2) = 5, we can start by expanding the left-hand side using the FOIL method:

(3x-2)(3x+2) = 9x^2 - 4

Now we can substitute this expression into the original equation:

9x^2 - 4 = 5

Simplifying further:

9x^2 = 9

Taking the square root of both sides, we get:

x = ±1

Therefore, the solutions to the equation (3x-2)(3x+2) = 5 are x = 1 and x = -1.