Question

(х-2)²-2 (х-2) (х+2)+(х+2)² При=х=3/7 ( 3 дробь 7 )

Answer 1

((x-2)-(x+2))^2=(x-2-x-2)^2=(-4)^2=16

Answer 2

To evaluate the expression (х-2)²-2 (х-2) (х+2)+(х+2)² when x=3/7, we need to substitute 3/7 for x and simplify:

(3/7 - 2)² - 2(3/7 - 2)(3/7 + 2) + (3/7 + 2)² = (-11/7)² - 2(-11/7)(23/7) + (23/7)² = 121/49 + 506/49 + 529/49 = 1156/49

Therefore, when x=3/7, the expression evaluates to 1156/49.