Question

Помогите решить плиз 1. A) m-2/4m+m-3/6m= Б) a²b/12c·4c/ab²= В) 56y²/a²÷16y³= 2. 2x²-9x+10=0 (Это через дискриминант)

Answer 1

Решение задания приложено

Answer 2

A) To simplify the expression, we need to find a common denominator for the two fractions in the equation:

m-2/4m + m-3/6m = (3(m-2)/(34m)) + (2(m-3)/(26m))

Simplifying this gives:

(m-2)/4m + (m-3)/9m

Now we can find a common denominator of 36m:

(9(m-2) + 4(m-3))/36m = (9m - 18 + 4m - 12)/36m

Simplifying the numerator:

(13m - 30)/36m

So the final answer is:

(m-2)/4m + (m-3)/6m = (13m-30)/36m

B) To simplify the expression:

a²b/12c · 4c/ab²

We can cancel out the common factor of ab:

a²b/12c · 4c/ab² = b/3c · 4c/a = 4b/3a

C) To simplify the expression:

56y²/a² ÷ 16y³

We can simplify this by dividing 56 by 16, and moving the y³ term from the denominator to the numerator:

56y²/a² ÷ 16y³ = 7y²/a² ÷ 2y³ = 7/2y^(2-3)/a² = 7/2y^-1/a² = 7a²/2y

2. To solve the quadratic equation 2x²-9x+10=0 using the discriminant, we first need to identify the values of a, b, and c in the general quadratic equation form:

ax² + bx + c = 0

In this case, a = 2, b = -9, and c = 10.

Next, we can calculate the discriminant, which is given by:

b² - 4ac

Plugging in the values:

(-9)² - 4(2)(10) = 81 - 80 = 1

Since the discriminant is positive, there are two real roots to this equation. We can use the quadratic formula to find these roots:

x = (-b ± sqrt(b² - 4ac))/2a

Plugging in the values:

x = (9 ± sqrt(1))/4

This simplifies to:

x = 5/2 or x = 2

So the solutions to the equation 2x²-9x+10=0 are x=5/2 or x=2.