Question

1) (12y+18)(1,6-0,2y)=0                  2) 4(2x-1)-3x=5x-4   

Answer 1

12у+18=0  или 1,6-0,2у=0
у=-18/12           у=-1,6/-0,2
у=-1,5               у=8
Ответ: у=-1,5 или у=8
4(2x-1)-3x=5x-4 
8х-4-3х-5х+4=0
0=0
х-любое
Ответ: х-множество действительных чисел

Answer 2

To solve the equation (12y+18)(1,6-0,2y) = 0, we need to find the values of y that make the expression equal to zero.

Using the distributive property, we can expand the expression as follows:

12y(1.6) - 12y(0.2y) + 18(1.6) - 18(0.2y) = 0

Simplifying, we get:

19.2y - 2.4y^2 + 28.8 - 3.6y = 0

Rearranging and factoring out y, we get:

-2.4y^2 + 15.6y + 28.8 = 0

Dividing both sides by -2.4, we get:

y^2 - 6.5y - 12 = 0

Using the quadratic formula, we can find the solutions for y:

y = (6.5 ± sqrt(6.5^2 - 4(1)(-12))) / (2(1))

y = (6.5 ± sqrt(169)) / 2

y = 9.25/2 or y = -2.75

Therefore, the solutions for the equation are y = 9.25/2 or y = -2.75.

To solve the equation 4(2x-1)-3x=5x-4, we need to simplify and isolate the variable x.

First, we can simplify the left side of the equation by distributing the 4:

8x - 4 - 3x = 5x - 4

Next, we can combine like terms:

5x - 4 = 5x - 4

This equation is an identity, which means that it is true for all values of x. Therefore, there are infinitely many solutions to this equation.

We can check this by plugging in any value for x, and we will find that both sides of the equation are equal. For example, if we let x = 0, we get:

4(2(0)-1)-3(0) = 5(0)-4

-4 = -4

This shows that x = 0 is a solution to the equation, but it is not the only solution.