Question

А)(x-3)(2x+9)=0 в)t^2+6t+9=0

Answer 1

A) (x-3)*(2x+9)=0
x-3=0
2x+9=0
x=3
x=-3/2
x1=-2/9 x2=3

Б)  t^2+6t+9=0
(t+3)^2=0
t^2+6t+9=0
(t+3)^2=0
T+3=0
t=-3

Answer 2

А)

To solve the equation (x-3)(2x+9)=0, we can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero. Therefore:

(x-3)(2x+9) = 0 x-3 = 0 or 2x+9 = 0 x = 3 or x = -4.5

Therefore, the solutions to the equation are x = 3 and x = -4.5.

B)

To solve the equation t^2+6t+9=0, we can use the quadratic formula:

t = (-b ± sqrt(b^2-4ac)) / 2a

Where a, b, and c are the coefficients of the quadratic equation in standard form, ax^2+bx+c=0.

In this case, a=1, b=6, and c=9. Substituting these values into the quadratic formula, we get:

t = (-6 ± sqrt(6^2 - 4(1)(9))) / 2(1) t = (-6 ± sqrt(0)) / 2 t = -3

Therefore, the only solution to the equation is t = -3.