Question

(а+в)^2-с^2/а+в+с а^2-8а+16/ах-4х. При а=-5 х=23х^2-ху/9х^2-6ху+у^2 при х=3/4,у=-2/3

Answer 1

2) -5^2-8-5+16/-5·2-4·2

3) 3·3/4^2-3/4·(-2/3)/ 9-3/4^2-6·3/4·(-2/3)+2/3^2

Answer 2

To solve these problems, we simply substitute the given values of the variables and simplify the expressions using algebraic operations.

For the first expression, we have:

(а+в)^2-с^2/а+в+с = [(a+b)^2 - c^2]/(a+b+c)

Substituting the values a = -5, b = unknown, c = unknown, we get:

((-5+b)^2 - c^2)/(-5+b+c)

For the second expression, we have:

a^2-8a+16/aх-4х = (a-4)^2/(ax-4x)

Substituting the values a = -5, x = unknown, we get:

(-5-4)^2/(-5x-4x) = 81/(-9x)

For the third expression, we have:

х=23х^2-ху/9х^2-6ху+у^2

Substituting the values x = 3/4, y = -2/3, we get:

3/4 = 23(3/4)^2 - (3/4)(-2/3)/(9(3/4)^2 - 6(3/4)(-2/3) + (-2/3)^2)

Simplifying the expression inside the parentheses, we get:

9/16 = 23(9/16) + 1/4 / (81/16 + 4/9 + 4/9)

Simplifying further, we get:

3/4 = 3/4, which is a true statement.

Therefore, the solutions for the given expressions are:

• For the first expression: ((-5+b)^2 - c^2)/(-5+b+c)
• For the second expression: 81/(-9x)
• For the third expression: 3/4.