Question

(5х-1)в квадрате -(1-3х)в квадрате =16х*(х-3)

Answer 1

Задание решено......

Answer 2

Let's start by expanding the squares on both sides of the equation:

(5x - 1)² - (1 - 3x)² = 16x*(x - 3)

Expanding the left-hand side:

(5x - 1)² = (5x)² - 2(5x)(1) + 1 = 25x² - 10x + 1

(1 - 3x)² = (1)² - 2(1)(3x) + (3x)² = 1 - 6x + 9x²

Substituting back into the original equation:

25x² - 10x + 1 - (1 - 6x + 9x²) = 16x*(x - 3)

25x² - 10x + 1 - 1 + 6x - 9x² = 16x² - 48x

16x² - 4x - 48x = 0

16x² - 52x = 0

4x(4x - 13) = 0

So x = 0 or x = 13/4.

Therefore, the solutions to the original equation are x = 0 and x = 13/4.