Question

Обчислыть:4 arccos 0 + 18 arctg (- √3/3)

Answer 1

4*π/2+18*(-π/6)=2π-3π=-π
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Answer 2

We can start by using the fact that the arccosine of 0 is equal to pi/2 (or 90 degrees), since the cosine function is equal to 0 at pi/2 and its multiples.

So, we have:

4 arccos 0 = 4 * pi/2 = 2*pi

Next, we can use the fact that the arctangent of -sqrt(3)/3 is equal to -pi/6 (or -30 degrees), since the tangent function is equal to -sqrt(3)/3 at -pi/6 and its odd multiples.

So, we have:

18 arctg (-sqrt(3)/3) = 18 * (-pi/6) = -3*pi

Therefore, the value of the expression 4 arccos 0 + 18 arctg (-sqrt(3)/3) is:

2pi + (-3pi) = -pi

Hence, the answer is -pi (or -180 degrees).