Question

1) (8х+4y)². 2) (4x+5)²-40x. 3) 50a²-(7a-1)²​

Answer 1

1. 64х2 ( х в квадрате ) + 64ху + 16у2 ( у в квадрате )
2. 16х2 ( х в квадрате ) + 40х + 25 -40х = 16х2+25
3. 50а2 - 49а2 - 14а + 1 = -а - 14а +1

Answer 2

1. Expanding the expression (8x+4y)² using the formula (a+b)² = a² + 2ab + b², we get:

(8x+4y)² = (8x)² + 2(8x)(4y) + (4y)² = 64x² + 64xy + 16y²

Therefore, (8x+4y)² = 64x² + 64xy + 16y².

2. Expanding the expression (4x+5)²-40x using the same formula, we get:

(4x+5)²-40x = (4x)² + 2(4x)(5) + 5² - 40x = 16x² + 40x + 25 - 40x = 16x² + 25

Therefore, (4x+5)²-40x = 16x² + 25.

3. Expanding the expression 50a²-(7a-1)² using the formula (a-b)² = a² - 2ab + b², we get:

50a² - (7a-1)² = 50a² - (7a)² + 2(7a)(1) - 1² = 50a² - 49a² + 14a - 1 = a² + 14a - 1

Therefore, 50a² - (7a-1)² = a² + 14a - 1.