Question

14-(2+3x-x^2)=x^2+4x-8 Решити рiвняння

Answer 1

28+42х-14х²=x²+4x-8

42x-14x²-x²-4x=-8-28

38x-13x²=-30

А дальше как не знаю

Answer 2

To solve the equation 14 - (2 + 3x - x^2) = x^2 + 4x - 8, we can start by simplifying the left-hand side:

14 - (2 + 3x - x^2) = 14 - 2 - 3x + x^2 = 12 + x^2 - 3x

So the equation becomes:

12 + x^2 - 3x = x^2 + 4x - 8

We can simplify this by moving all the terms to one side of the equation:

12 - 8 = 4x - x^2 + 3x - x^2 4 = -x^2 + 7x - 8 0 = x^2 - 7x + 12

Now we can factor the quadratic expression on the right-hand side:

0 = (x - 3)(x - 4)

So the solutions to the equation are x = 3 and x = 4.

Therefore, the solution set for the equation 14 - (2 + 3x - x^2) = x^2 + 4x - 8 is {3, 4}.