Question

-5x+3y=11 5x+4y=3 Способом алгебраического сложения решить систему уравнений

Answer 1

Сложим оба уравнения, получим: 7у = 20; у = 20/7
5x+4y=3
5x+4*20/35=3
x=3/5-80/35
х = 21/35-80/35 = -59/35

Answer 2

7y = 14
y=2

5x+4y=3
5x+8=3
5x=-5
x = -1

Ответ: (-1;2)

Answer 3

To solve this system of equations by the method of algebraic addition, we need to add the two equations together in such a way that one of the variables is eliminated. Let's begin:

-5x + 3y = 11 5x + 4y = 3

If we add these two equations together, we can eliminate x:

-5x + 3y + 5x + 4y = 11 + 3

Simplifying:

7y = 14

Dividing both sides by 7:

y = 2

Now we can substitute this value of y back into one of the original equations to solve for x:

-5x + 3(2) = 11

Simplifying:

-5x + 6 = 11

Subtracting 6 from both sides:

-5x = 5

Dividing both sides by -5:

x = -1

Therefore, the solution to the system of equations is x = -1 and y = 2.