Question

(3x+4)²-(3x-1)(1+3x)=49

Answer 1

9x^2+24x+16-(3x+9x^2-1-3x)=49
9x^2+24x+16-3x-9x^2+1+3x=49
24x=32
x=4/3

Answer 2

To solve the given equation, let's simplify the expression first:

(3x + 4)² - (3x - 1)(1 + 3x) = 49

Expanding the square: (9x² + 24x + 16) - (3x - 1)(1 + 3x) = 49

Now, let's expand the second term using the distributive property: (9x² + 24x + 16) - (3x - 1)(1) - (3x - 1)(3x) = 49

Simplifying further: 9x² + 24x + 16 - (3x - 1) - 3x(3x - 1) = 49

Next, distribute -1 and -3x to each term inside the parentheses: 9x² + 24x + 16 - 3x + 1 - 9x² + 3x = 49

Combine like terms: 9x² - 9x² + 24x - 3x + 3x + 16 + 1 = 49

Simplify: 24x + 17 = 49

Now, isolate the variable: 24x = 49 - 17 24x = 32

Divide both sides by 24: x = 32 / 24 x = 4/3

So, the solution to the equation is x = 4/3.