Question

Решите плиз 28x-8x^2=12

Answer 1

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Answer 2

28х-8х²=12
нужно представить так
ах²+bx+c=0
-8x²+28x-12=0
умножаем на -1 и меняем знаки
8х²-28х+12=0
D=28²-4*8*12=784-384=√400
x1=28+20/8*2=48/16=3
x2=28-20/8*2=8/16=1/2=0,5

Answer 3

To solve the equation 28x - 8x^2 = 12, we first need to rearrange it into a standard quadratic form, which is ax^2 + bx + c = 0.

We can do this by moving all the terms to one side of the equation:

8x^2 - 28x + 12 = 0

Next, we can simplify the quadratic by dividing all the terms by the common factor of 4:

2x^2 - 7x + 3 = 0

Now we have a quadratic equation in standard form. To solve for x, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

In this case, a = 2, b = -7, and c = 3, so:

x = (-(-7) ± sqrt((-7)^2 - 4(2)(3))) / (2(2)) x = (7 ± sqrt(49 - 24)) / 4 x = (7 ± sqrt(25)) / 4

So the two solutions to the equation are:

x = (7 + 5) / 4 = 3 x = (7 - 5) / 4 = 1/2

Therefore, the solutions to the equation 28x - 8x^2 = 12 are x = 3 and x = 1/2.