Question

X²=25 5x³-5x=0 2x+3=109 -5x+101=6 152x=0 x=0

Answer 1

Как-то так, надеюсь, помог

Answer 2

Let's go through each equation one by one and solve for the value of x.

1. x² = 25: Taking the square root of both sides, we get: x = ±√25 Therefore, x can be either 5 or -5.

2. 5x³ - 5x = 0: Factoring out 5x from the equation, we have: 5x(x² - 1) = 0 Applying the zero-product property, we have two cases: Case 1: 5x = 0 Dividing both sides by 5, we get: x = 0 Case 2: x² - 1 = 0 Adding 1 to both sides, we get: x² = 1 Taking the square root of both sides, we have: x = ±√1 Therefore, x can be either 1 or -1.

3. 2x + 3 = 109: Subtracting 3 from both sides, we get: 2x = 109 - 3 2x = 106 Dividing both sides by 2, we get: x = 53

4. -5x + 101 = 6: Subtracting 101 from both sides, we get: -5x = 6 - 101 -5x = -95 Dividing both sides by -5, we get: x = 19

5. 152x = 0: Dividing both sides by 152, we get: x = 0

To summarize the solutions: x = 5, -5, 0, 1, -1, 53, and 19.