Question

2arccos (-1) -arcsin1 + arcctg (-1)

Answer 1

Ответ: arccos(-1)=pi, arcsin(1)=pi/2, arcctg(-1)=-0,25*pi. Тогда заданное выражние перепишем как - 2*pi-0,5*pi-0,25*pi=-2,75*pi.

Объяснение:

Answer 2

To calculate the expression 2arccos(-1) - arcsin(1) + arcctg(-1), let's break it down step by step:

1. The value of arccos(-1) is π. Since the arccosine function returns the angle whose cosine is a given value, cos(π) equals -1.

2. The value of arcsin(1) is π/2. The arcsine function returns the angle whose sine is a given value, sin(π/2) equals 1.

3. The value of arcctg(-1) is -π/4. The arc cotangent function (also known as arccot or arcctg) returns the angle whose cotangent is a given value. cot(-π/4) equals -1.

Now, substituting the values into the expression:

2arccos(-1) - arcsin(1) + arcctg(-1) becomes 2π - π/2 + (-π/4)

To simplify further, we can find a common denominator for the fractions:

2π - π/2 + (-π/4) = (8π - π - 2π)/4 = (5π - π)/4 = 4π/4 = π

Therefore, the value of the expression 2arccos(-1) - arcsin(1) + arcctg(-1) is π (pi).