Question

|х+12|=3 ХЭЭЭЭЭЭЭЭЭЛП

Answer 1

Х+12>0
x+12 = 3
x = -9

x+12<0
-x-12 = 3
-x = 9
x = -9
Ответ: х = -9

Answer 2

X+12=3
x=-12+3
x=-9 вродебы так , ведь модул есть

Answer 3

To solve the equation |x + 12| = 3, we need to consider two cases: when the expression inside the absolute value is positive and when it is negative.

Case 1: x + 12 is positive In this case, we can remove the absolute value symbols and set the expression inside the absolute value equal to the right-hand side of the equation, which is 3. So we have: x + 12 = 3

To isolate x, we subtract 12 from both sides of the equation: x + 12 - 12 = 3 - 12 x = -9

So one solution is x = -9.

Case 2: x + 12 is negative In this case, the expression inside the absolute value becomes its negation. So we have: -(x + 12) = 3

To solve for x, we need to distribute the negative sign to both terms inside the parentheses: -x - 12 = 3

Now, to isolate x, we add 12 to both sides of the equation: -x - 12 + 12 = 3 + 12 -x = 15

To solve for x, we multiply both sides of the equation by -1 (to change the sign of x): -1 * (-x) = -1 * 15 x = -15

So another solution is x = -15.

Therefore, the equation |x + 12| = 3 has two solutions: x = -9 and x = -15.