Question

(x-3)²-(x-1)(x-4)+(x-2)(x+2)= ... ​

Answer 1

Ответ:

=x*2+6x+9-（x*2-4x-x+4)+x*2+2x-2x-4=x*2-6x+9-x*2+5x-4+x*2+2x-2x-4=x*2-x+1

Объяснение:

x*2-x+1

Answer 2

Let's simplify the given expression step by step:

First, let's expand the squared term: (x - 3)² = (x - 3)(x - 3) = x² - 3x - 3x + 9 = x² - 6x + 9

Next, let's expand the product terms: (x - 1)(x - 4) = x² - 4x - x + 4 = x² - 5x + 4

(x - 2)(x + 2) = x² + 2x - 2x - 4 = x² - 4

Now, we can substitute these expanded terms back into the original expression: (x - 3)² - (x - 1)(x - 4) + (x - 2)(x + 2) = (x² - 6x + 9) - (x² - 5x + 4) + (x² - 4)

Simplifying further by removing parentheses and combining like terms:

= x² - 6x + 9 - x² + 5x - 4 + x² - 4 = x² - x² + x² - 6x + 5x + 9 - 4 - 4 = 0x² - x + 1

Therefore, the simplified form of the expression (x - 3)² - (x - 1)(x - 4) + (x - 2)(x + 2) is: -x + 1