Question

A(b-3a)^2/3a^2-ab  -3a/1 при a=2,18 b= -5,6

Answer 1

A = 2,18; b = -5,6
a(b-3a)^2/(3a^2-ab) - 3a/1 = (ab-3a^2)(b-3a)/(3a^2-ab) - 3a = -(b-3a) - 3a = -b
-b = - (-5,6) = 5,6

Answer 2

Скорее всего, в условии не хватает скобок в числителе (3a^2-ab).

Answer 3

To evaluate the expression, substitute the given values for a and b:

A(b - 3a)^2 / (3a^2 - ab) - (3a / 1) = A((-5,6) - 3(2,18))^2 / (3(2,18)^2 - (2,18)(-5,6)) - (3(2,18) / 1)

Simplifying the expression:

A((-5,6) - 6,54)^2 / (6,54^2 + 12,428) - 6,54

Now you can substitute the given values for A, a, and b and perform the calculations.