Question

(x-5)^2=(x-8)^2 !!!!!!!

Answer 1

(x-5)² =(x-8)²
x² -10x+25= x² -16x+64
6x= 39
x=39/6
x=6,5

Answer 2

(x-5)²-(x-8)²=0
(x-5-x+8)(x-5+x-8)=0
3*(2x-13)=0

2x-13=0
2x=13
x=13:2
x=6,5

Answer 3

To solve the equation $(x-5)^2 = (x-8)^2$, we can begin by expanding both sides and simplifying the equation.

Expanding the equation, we have:

$(x-5)(x-5) = (x-8)(x-8)$

Simplifying further, we have:

$x^2 - 10x + 25 = x^2 - 16x + 64$

Next, we can eliminate the common terms on both sides of the equation by subtracting $x^2$ from both sides:

$-10x + 25 = -16x + 64$

Let's continue solving for $x$:

Subtracting $-25$ from both sides:

$-10x = -16x + 39$

Adding $16x$ to both sides:

$-10x + 16x = 39$

Simplifying:

$6x = 39$

Finally, we solve for $x$ by dividing both sides by $6$:

$x = \frac{39}{6}$

Simplifying the fraction, we have:

$x = 6.5$

So, the solution to the equation $(x-5)^2 = (x-8)^2$ is $x = 6.5$.