Answer 1

$\frac{(x-4)^2}{3} - \frac{(x+4)^2}{3} =5\, |\cdot 3\\\\(x-4)^2-(x+4)^2=15\\\\x^2-8x+16-(x^2+8x+16)=15\\\\-16x=15\\\\x=-\frac{15}{16}=-0,9375$

Answer 2

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