Question

(9х-7)/(3х-2) - (4х-5)/(2х-3)=1​

Answer 1

Ответ:

1

Объяснение:

Подбором получилось

Но если че, photomath должен решить

Answer 2

To solve the equation:

(9x - 7)/(3x - 2) - (4x - 5)/(2x - 3) = 1

We'll begin by finding a common denominator for the two fractions on the left side of the equation, which is (3x - 2)(2x - 3):

[(9x - 7)(2x - 3)]/[(3x - 2)(2x - 3)] - [(4x - 5)(3x - 2)]/[(2x - 3)(3x - 2)] = 1

Next, we'll simplify the numerators:

(18x^2 - 27x - 14x + 21)/(6x^2 - 9x - 4x + 6) - (12x^2 - 16x - 15x + 10)/(6x^2 - 9x - 4x + 6) = 1

Combining like terms in the numerators:

(18x^2 - 41x + 21)/(6x^2 - 13x + 6) - (12x^2 - 31x + 10)/(6x^2 - 13x + 6) = 1

Since the denominators are now equal, we can combine the fractions:

(18x^2 - 41x + 21 - 12x^2 + 31x - 10)/(6x^2 - 13x + 6) = 1

Simplifying the numerator further:

(6x^2 - 10x + 11)/(6x^2 - 13x + 6) = 1

Now, let's multiply both sides of the equation by (6x^2 - 13x + 6) to eliminate the denominator:

(6x^2 - 10x + 11) = 1(6x^2 - 13x + 6)

Expanding the right side:

6x^2 - 10x + 11 = 6x^2 - 13x + 6

Next, we'll group like terms:

(6x^2 - 6x^2) + (-10x + 13x) + (11 - 6) = 0

Simplifying:

3x + 5 = 0

Subtracting 5 from both sides:

3x = -5

Dividing both sides by 3:

x = -5/3

Therefore, the solution to the equation is x = -5/3.