Question

Tg^2 П/3 - 2 cos П/3 + cos П/2 - sin 3П/2

Answer 1

$tg^{2}\frac{\pi }{3}-2Cos\frac{\pi }{3}+Cos\frac{\pi }{2}-Sin\frac{3\pi }{2}=(\sqrt{3})^{2}-2*\frac{1}{2}+0-(-1)=3-1+0+1=3$

Answer 2

Let's break down the expression step by step:

1. Tg^2(π/3): The symbol "Tg" is not a standard mathematical function. It seems you might be referring to the tangent function, often denoted as "tan." Assuming that's the case, we have tan^2(π/3) which means finding the tangent of π/3 and squaring the result.

The tangent of π/3 can be calculated as √3, so we have (√3)^2 = 3.

2. 2 cos(π/3): Here, we have the cosine of π/3, which is equal to 1/2. Multiplying it by 2 gives us 2 * (1/2) = 1.

3. cos(π/2): The cosine of π/2 is equal to 0.

4. sin(3π/2): The sine of 3π/2 is equal to -1.

Now, let's put all the values together:

3 - 2 + 0 - (-1) = 3 + 2 + 1 = 6

Therefore, Tg^2(π/3) - 2 cos(π/3) + cos(π/2) - sin(3π/2) equals 6.