Question

1) 5х²=25х 2) 100х²-16=0 3) 3х²-11х-4=0 4) х²-3х+1=0 5) 2х²+5х+9=х+2 6) (х-4)(4х+6)=(х-5)² 7) 3х²+6х/2=4-2х

Answer 1

2) 100x²=16; x²=16/100; x=√16/100; x=4/10=2/5, 3) наверно тут найти дискриминант...мы короче таким образом решали такую задачу)) D=(-11)²- 4·3·(-4)=121+ 48=169; √=13; x=11 ±13/6; x1=3; x2=-1/3; остальным рада бы помочь только у меня самой час дела(((надеюсь ты сам или кто нибудь поможет найти решение

Answer 2

Let's solve each of the equations one by one:

1. 5x² = 25x

To solve this equation, we can first subtract 25x from both sides to bring all terms to one side:

5x² - 25x = 0

Now we can factor out the common term of 5x:

5x(x - 5) = 0

From here, we can apply the zero product property, which states that if a product of factors is equal to zero, then at least one of the factors must be zero. So we have:

5x = 0 or x - 5 = 0

Solving each equation separately, we get:

x = 0 or x = 5

Therefore, the solutions to the equation are x = 0 and x = 5.

2. 100x² - 16 = 0

First, let's add 16 to both sides to isolate the quadratic term:

100x² = 16

Next, divide both sides by 100 to solve for x²:

x² = 16/100

Simplifying the right side gives us:

x² = 0.16

To solve for x, we can take the square root of both sides:

x = ±√0.16

x = ±0.4

Therefore, the solutions to the equation are x = -0.4 and x = 0.4.

3. 3x² - 11x - 4 = 0

To solve this quadratic equation, we can factorize it:

(3x + 1)(x - 4) = 0

Now we can apply the zero product property:

3x + 1 = 0 or x - 4 = 0

Solving each equation separately, we get:

3x = -1 or x = 4

Dividing by 3 in the first equation gives us:

x = -1/3

Therefore, the solutions to the equation are x = -1/3 and x = 4.

4. x² - 3x + 1 = 0

This quadratic equation doesn't factor easily, so we can use the quadratic formula to find the solutions. The quadratic formula states that for an equation in the form ax² + bx + c = 0, the solutions can be found using:

x = (-b ± √(b² - 4ac)) / (2a)

For this equation, a = 1, b = -3, and c = 1. Substituting these values into the quadratic formula:

x = (-(-3) ± √((-3)² - 4(1)(1))) / (2(1))

Simplifying further:

x = (3 ± √(9 - 4)) / 2

x = (3 ± √5) / 2

Therefore, the solutions to the equation are x = (3 + √5) / 2 and x = (3 - √5) / 2.

5. 2x² + 5x + 9 = x + 2

To solve this equation, we'll first bring all terms to one side:

2x² + 5x + 9 - x - 2 = 0

Simplifying:

2x² + 4x + 7 = 0

Unfortunately, this quadratic equation doesn't factor easily either. We can use the quadratic formula to find the solutions:

x = (-b ± √(b² - 4ac)) / (2a)

For this equation, a = 2,