Question

(x+5)²(6-c²)(-x-3)²​

Answer 1

х

${x}^{2} + 25$

$6 - {y}^{2}$

${ - x}^{2} - 9$

Answer 2

ответ во вложении, вроде правильно

Answer 3

To simplify the expression $(x+5)^2(6-c^2)(-x-3)^2$, we can start by expanding each squared binomial:

$(x+5)^2 = (x+5)(x+5) = x^2 + 10x + 25$

$(-x-3)^2 = (-x-3)(-x-3) = x^2 + 6x + 9$

Now we can substitute these expansions back into the original expression:

$(x+5)^2(6-c^2)(-x-3)^2 = (x^2 + 10x + 25)(6-c^2)(x^2 + 6x + 9)$

To simplify further, we can multiply the terms together:

$(x^2 + 10x + 25)(6-c^2)(x^2 + 6x + 9) = (6-c^2)(x^2 + 10x + 25)(x^2 + 6x + 9)$

Now we can expand each term:

$(6-c^2)(x^2 + 10x + 25)(x^2 + 6x + 9) = (6-c^2)(x^4 + 16x^3 + 109x^2 + 340x + 225)$

Finally, we can distribute the remaining factor $(6-c^2)$ across each term:

$(6-c^2)(x^4 + 16x^3 + 109x^2 + 340x + 225) = 6x^4 + 96x^3 + 654x^2 + 2040x + 1350 - c^2x^4 - 16c^2x^3 - 109c^2x^2 - 340c^2x - 225c^2$

So, the simplified form of the expression $(x+5)^2(6-c^2)(-x-3)^2$ is $6x^4 + 96x^3 + 654x^2 + 2040x + 1350 - c^2x^4 - 16c^2x^3 - 109c^2x^2 - 340c^2x - 225c^2$.