Question

(-3а-² )-³ 9a^-5 (————) · ------------ = ( b. ) b²

Answer 1

=(-3/a²b)^-3 *(9/a^5b²) =(a^6b^3)/(-27) *(9/a^5b²) =(9a^6b^3) /(-27a^5b²) =
-ab/3

Answer 2

To simplify the expression, let's break it down step by step:

First, let's simplify the expression (-3a^-2)^-3: (-3a^-2)^-3 = (-3)^-3 * (a^-2)^-3 = (-3)^-3 * a^6 (using the property (x^m)^n = x^(m*n)) = (-1/27) * a^6 (since (-3)^-3 = -1/27)

Next, let's simplify the expression 9a^-5/(b^2): 9a^-5/(b^2) = 9/a^5 * 1/(b^2) = 9/(a^5 * b^2)

Now, let's combine the two expressions: ((-3a^-2)^-3) * (9a^-5/(b^2)) = ((-1/27) * a^6) * (9/(a^5 * b^2)) = -1/3 * a * (a/a^5) * (1/b^2) = -1/3 * (1/a^4) * (1/b^2) = -1/(3a^4b^2)

So, the simplified expression is -1/(3a^4b^2).