Question

A) (2x-y)(x+y) б) (a+b)(2a+3b) в) (3c+a)(2c-a) г) (6z-y)(2z-y)

Answer 1

А) 2x2 + 2xy-xy-y2= 2x2+xy-y2
Б)2a2 + 3ab +2ab + 3b2 = 2a2 + 5ab +!3b2
В)6c2 -3ac +2ac -a2 = 6c2 - ac - a2
Г)12z2 -6zy-2zy + y2 = 12z2 -8zy + y2

Answer 2

A) To expand the expression (2x-y)(x+y), you can use the distributive property:

(2x-y)(x+y) = 2x(x+y) - y(x+y)

Now, apply the distributive property again:

= 2x * x + 2x * y - y * x - y * y

Simplify further:

= 2x^2 + 2xy - xy - y^2

Combining like terms:

= 2x^2 + xy - y^2

Therefore, the